Kalinina was defeated in the 1/8 finals of the WTA tournament in Charleston

Angelina lost all nine games on her serve

Ukrainian tennis player Angelina Kalinina failed to make it to the quarterfinals of the tournament WTA 500 in American Charleston.

In the 1/8 finals match, Kalinina lost to Daria Kasatkina, who competes under a neutral flag. The fight lasted an hour and 25 minutes.

In the first set, Angelina was unable to oppose anything to the fourth seed – 1:6. In the second game, the Ukrainian lost with a score of 4:6.

Note that Kalinina lost all nine games on her serve, making five breaks in response. The Ukrainian also made two double faults.

On the night of April 4-5, Elina Svitolina will host the 1/8 finals match. The rival of the first racket of Ukraine is Elise Mertens from Belgium.

Let us remind you that Dayana Yastremskaya and Lesya Tsurenko were unable to overcome the second round of the tournament in Charleston.


  • WTA 500. Charleston, USA. 1/8 finals

Daria Kasatkina (-, 4) — Angelina Kalinina (Ukraine, 15) 2:0 (6:1, 6:4)

Source: Sportarena

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