Liberty and Fever players, respectively, were invited by the women’s league All-Star organization, but both decided to decline their participation.
A new edition of the WNBA All-Star Game will be held tonight at the Footprint Center in Arizona and one of the stars of the New York franchise, the Liberty, Sabrina Ionescu, will be the big absentee in the three-point contest. And as if that wasn’t enough, Caitlin Clark is another one of those who won’t be joining. According to reports, both figures were invited, but both decided not to be part of the billboard. And although the reason for the refusal was not formally announced, everything indicates that the economic incentive for such a presence is low, as reported by Lev Akabas from NY.
Apparently, The amount they will pay the players is $1,030, while the prize for winning is $2,575 Considering that Clark, for example, signed a contract for $28 million, there is no need to risk the physical for a low price for him .
This season, Ionescu is the second player making the most triples per game, with three conversions per game, behind Kayla McBride, with a success percentage of 35.6%. Caitlin Clark is in fifth place, converting 2.7 per night, with a 32.7% success rate.
Without Ionescu or Clark, the three-point contest ends with Jonquel Jones, of the New York Liberty; Allisha Gray, of the Atlanta Dream; Marina Mabrey of the Connecticut Sun; Stefanie Dolson of the Washington Mystics; and Kayla McBride of the Minnesota Lynx. The event starts at 10 pm (Argentine time).
Source: Tycsports
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