Russian tennis player Andrei Rublev reached the fourth round of the Australian Open.
In the third round, Rublev, who received the fifth seed, defeated American Sebastian Korda (29) with a score of 6:2, 7:6 (8:6), 6:4. The athletes spent 1 hour 59 minutes on the field.
In the next round, the Russian will face Australian Alex de Minaur (10).
GRAND Slam TOURNAMENT. AUSTRALIAN OPEN. MELBOURNE, AUSTRALIA). HARD. TOTAL PRIZE HARVEST – OVER $59 MILLION
MEN. 3rd CIRCLE
Andrey Rublev (Russia, 5 years old) — Sebastian Korda (USA, 29) — 6:2, 7:6 (8:6), 6:4
Source : MatchTV

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