Russian tennis player Andrei Rublev reached the semi-finals of the tournament in Sweden’s Bostad, beating Serbian Laszlo Gyor.
In the quarterfinal match, Rublev won in two games, making a total of three breaks. The match lasted 1h30, the Russian scored 2 aces and made 2 double faults, his opponent made 7 aces.
Rublev’s rival, seeded under the second number, in the semi-final will be the 8th racket of the tournament the Argentinian Sebastian Baez, who had previously knocked out Dominic Thiem.
ATP 250 tournament. Bostad (Sweden). Priming. The prize fund is more than 530,000 euros
Quarterfinal
Andrey Rublev (Russia, 2) – Laszlo Djere (Serbia) – 7:5, 6:4
Source : MatchTV

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