Rublev failed to qualify for fourth round of Indian Wells tournament

Russian Andrei Rublev lost to Czech tennis player Jiri Legechka in the third round of the Indian Wells tournament.

The fifth racket of the tournament, Rublev, lost to his opponent in straight sets; tennis players spent 1 hour and 13 minutes on the court. The Russian made a serve and committed a double fault. Leeckka had 9 aces and two double faults.

In the next round, Legechka will meet Greek Stefan Tsitsipas (11th seed).

The second racket in the world, the Spaniard Carlos Alcaraz, easily faced the Canadian Felix Auger-Alassime, the representative of Kazakhstan Alexander Bublik lost to the Australian Alex De Minaur.

WTA 1000. BNP PARIBAS OPEN. Indian Wells (United States). Hard. Prize Fund – over $9.2 million

Third circle

Jiri Legechka (Czech Republic, 32 years old) — Andrey Rublev (Russia, 5 years old) —6:4, 6:4

Carlos Alcaraz (Spain, 2) – Felix Auger-Alassime (Canada, 31) – 6:2, 6:3

Alex De Minaur (Australia, 10) – Alexander Bublik (Kazakhstan, 20) – 7:5, 6:0

Source : MatchTV

Related articles

Comments

LEAVE A REPLY

Please enter your comment!
Please enter your name here

Share article

Latest articles

Newsletter

Subscribe to stay updated.